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2(x^2-3)+5x=x^2+11x-15
We move all terms to the left:
2(x^2-3)+5x-(x^2+11x-15)=0
We add all the numbers together, and all the variables
5x+2(x^2-3)-(x^2+11x-15)=0
We multiply parentheses
2x^2+5x-(x^2+11x-15)-6=0
We get rid of parentheses
2x^2-x^2+5x-11x+15-6=0
We add all the numbers together, and all the variables
x^2-6x+9=0
a = 1; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{6}{2}=3$
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